16x^2+27=2

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Solution for 16x^2+27=2 equation: 



16x^2+27=2

We move all terms to the left:

16x^2+27-(2)=0

We add all the numbers together, and all the variables

16x^2+25=0

a = 16; b = 0; c = +25;
Δ = b2-4ac
Δ = 02-4·16·25
Δ = -1600
Delta is less than zero, so there is no solution for the equation

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